Algebra Lineal David C Lay Solucionario

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7.1 SOLUTIONS

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Notes: Students can profit by reviewing Section 5.3 (focusing on the Diagonalization Theorem) before working on this section. Theorems 1 and 2 and the calculations in Examples 2 and 3 are important for the sections that follow. Note that symmetric matrix means real symmetric matrix, because all matrices in the text have real entries, as mentioned at the beginning of this chapter. The exercises in this section have been constructed so that mastery of the Gram-Schmidt process is not needed.

Theorem 2 is easily proved for the 2 2 case:

If ,a b

Solucionario

Ac d

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= then ( )2 21 ( ) 4 .2 a d a d b = + + If b = 0 there is nothing to prove. Otherwise, there are two distinct eigenvalues, so A must be diagonalizable.

In each case, an eigenvector for is .db

1. Since 3 5

,5 7

TA A = = the matrix is symmetric.

2. Since 3 5

Lineal

,5 3

TA A

= the matrix is not symmetric.

3. Format flash drive for mac large files. Since 2 2

Algebra Lineal David C Lay Solucionario Da

,4 4

TA A = the matrix is not symmetric.

Format flash drive mac fat32. 4. Download myanmar zawgyi font for mac. Since 0 8 38 0 2 ,3 2 0

TA A

Algebra lineal david c lay solucionario con

Algebra Lineal David C Lay Solucionario Con

= =

the matrix is symmetric.

5. Since 6 2 00 6 2 ,0 0 6

TA A

=

Solucionario Algebra Lineal David C Lay 3ra Edicion

the matrix is not symmetric.

Algebra Lineal David C Lay Solucionario E

6. Since A is not a square matrix TA A and the matrix is not symmetric.